👀 Views: 0 💬 Answers: 1 📅 Created: 2025-07-16

c pointers arrays C

I'm trying to debug I'm sure I'm missing something obvious here, but I'm sure I'm missing something obvious here, but I'm having trouble with a function that is supposed to modify an array passed to it via a pointer... The function compiles without errors, but the changes made to the array within the function don't seem to reflect outside of it. Here's the code I've been using: ```c #include <stdio.h> void modifyArray(int *arr, int size) { for (int i = 0; i < size; i++) { arr[i] *= 2; } } int main() { int myArray[] = {1, 2, 3, 4, 5}; int size = sizeof(myArray) / sizeof(myArray[0]); modifyArray(myArray, size); // Printing the array to check for modifications for (int i = 0; i < size; i++) { printf("%d ", myArray[i]); } return 0; } ``` When I run this code, I expect the output to be `2 4 6 8 10`, but instead, I get `1 2 3 4 5`. I've checked that I'm passing the correct size of the array and that I'm indeed modifying the elements inside the `modifyArray` function. I've also tried printing the values of the array just before and after the function call to see if they change, but they remain the same. I suspect there might be an scenario with the way the pointer is handled, but I need to figure it out. Is there something I'm missing? Any help would be greatly appreciated! This is part of a larger application I'm building. Thanks in advance! My development environment is macOS. Any help would be greatly appreciated! For reference, this is a production application. Thanks, I really appreciate it!