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Segmentation fault when attempting to access struct members with pointers in C

👀 Views: 0 đŸ’Ŧ Answers: 1 📅 Created: 2025-07-16
c pointers structs memory-management C

I'm sure I'm missing something obvious here, but I'm relatively new to this, so bear with me. I'm encountering a segmentation fault when trying to access members of a struct via a pointer in my C program. I'm working with a simple struct that represents a 2D point, and I have a function that initializes an array of these points. After populating the array, I attempt to access its elements using a pointer, but I end up with a segmentation fault. Here's a simplified version of my code: ```c #include <stdio.h> #include <stdlib.h> typedef struct { int x; int y; } Point; void initializePoints(Point **points, int size) { *points = malloc(size * sizeof(Point)); // Allocating memory for the array for (int i = 0; i < size; i++) { (*points)[i].x = i; (*points)[i].y = i * 2; } } int main() { Point *points = NULL; int size = 5; initializePoints(&points, size); // Attempting to access the struct members for (int i = 0; i <= size; i++) { // Oops! Off-by-one error here printf("Point %d: (%d, %d)\n", i, points[i].x, points[i].y); } free(points); return 0; } ``` When I run this code, I get a segmentation fault at the line where I attempt to print the points. I suspect it might be due to the loop condition `i <= size`, since I allocated memory for `size` elements but I'm trying to access `size + 1`. I've tried changing the loop to `i < size`, but I want to confirm if that's the cause of the segmentation fault or if there's something else at play. Can anyone shed some light on this? Is there a better way to handle dynamic memory allocation for structs in C, especially when dealing with arrays? For context: I'm using C on Linux.