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implementing Custom Comparator in Sorting Objects by Multiple Properties in TypeScript

πŸ‘€ Views: 14 πŸ’¬ Answers: 1 πŸ“… Created: 2025-07-24
typescript sorting comparator

I've searched everywhere and can't find a clear answer... I'm working on a TypeScript project where I need to sort an array of objects based on multiple properties. The objects represent users and have `name`, `age`, and `registrationDate` fields. I want to sort them first by `age` in ascending order and then by `registrationDate` in descending order if the ages are the same. I've implemented a custom comparator function for this, but I'm getting unexpected results that don't seem to respect the sorting criteria. Here’s the code I have: ```typescript interface User { name: string; age: number; registrationDate: Date; } const users: User[] = [ { name: 'Alice', age: 30, registrationDate: new Date('2023-01-01') }, { name: 'Bob', age: 30, registrationDate: new Date('2022-12-01') }, { name: 'Charlie', age: 25, registrationDate: new Date('2023-03-01') }, { name: 'David', age: 40, registrationDate: new Date('2021-05-01') } ]; const sortUsers = (a: User, b: User) => { if (a.age === b.age) { return b.registrationDate.getTime() - a.registrationDate.getTime(); // Descending order for registrationDate } return a.age - b.age; // Ascending order for age }; users.sort(sortUsers); console.log(users); ``` When I run this code, I expect the output to have users sorted by age first and then by registration date as specified. However, the result seems to not respect the grouping by age. For instance, users with the same age are not sorted correctly by registration date. I also checked the console, and I don’t see any errors, just incorrect output. I'm using TypeScript version 4.5.2. Am I missing something in the comparator logic or how the `sort` method works? Any insights or suggestions would be greatly appreciated!