Bash script scenarios to handle variable expansion within nested functions
I'm migrating some code and I'm testing a new approach and I recently switched to I'm optimizing some code but I'm working on a project and hit a roadblock. I'm working with an scenario with variable expansion in my Bash script. I have a scenario where I define a variable inside a nested function, but it seems like the parent function is not able to access this variable after the nested function finishes executing. Here's a simplified version of my script: ```bash #!/bin/bash outer_function() { local outer_var="I'm outside!" inner_function() { local inner_var="I'm inside!" echo "$inner_var" } inner_function echo "$inner_var" # This line causes an behavior } outer_function ``` When I run this script, I get the following behavior: ``` ./script.sh: line 8: inner_var: unbound variable ``` I expected that `inner_var` would be accessible after calling `inner_function`, but it seems to be limited to its scope. I've tried using different types of variable declarations (like removing `local`), but that doesn't change the behavior. How can I modify my script so that `outer_function` can access `inner_var`? Is there a way to return the value from `inner_function` or store it in a way that `outer_function` can use it? Any help would be appreciated! My development environment is Windows. What's the best practice here? The stack includes Bash and several other technologies. This is my first time working with Bash latest. Any ideas how to fix this? This is my first time working with Bash 3.10. Any ideas what could be causing this? I'm coming from a different tech stack and learning Bash. Is there a better approach? For reference, this is a production service.