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Sorting User Objects by Age and Last Name in Python - implementing Ties

👀 Views: 60 đŸ’Ŧ Answers: 1 📅 Created: 2025-08-07
python sorting custom-comparator Python

I'm working on a project and hit a roadblock. I'm trying to figure out I tried several approaches but none seem to work. I'm trying to sort a list of user objects in Python based on their age and last name. Here's what my user class looks like: ```python class User: def __init__(self, name, age): self.name = name self.age = age def __repr__(self): return f'{self.name} ({self.age})' ``` I have a list of users like this: ```python users = [ User('Alice', 30), User('Bob', 25), User('Charlie', 30), User('David', 35), User('Eve', 25) ] ``` I want to sort first by age in ascending order and then by last name in alphabetical order in case of age ties. So I tried using the `sorted` function with a custom key: ```python sorted_users = sorted(users, key=lambda x: (x.age, x.name)) ``` However, I ran into an unexpected scenario. The output I received was not what I expected: ``` [Bob (25), Eve (25), Alice (30), Charlie (30), David (35)] ``` I expected 'Alice' to come before 'Charlie' since they have the same age. After some debugging, I realized that the sorting is working as designed, but I'm not sure how to correctly implement the comparison based on names. Can anyone suggest a reliable method to handle this? I'm using Python 3.9.1. Should I implement a different sorting approach, or is there a way to enhance the lambda function for better handling of ties in this case? Any insights would be greatly appreciated! This is part of a larger CLI tool I'm building. Thanks in advance! This issue appeared after updating to Python latest. Any feedback is welcome! For reference, this is a production mobile app.