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How to Properly Use Go Channels for Buffered Communication Without Deadlocks?

👀 Views: 0 💬 Answers: 1 📅 Created: 2025-08-22
go channels concurrency Go

I'm working on a project and hit a roadblock. I tried several approaches but none seem to work. I'm currently working on a Go application that uses buffered channels for communication between goroutines. I've set up a buffered channel to handle messages, but I'm working with a deadlock scenario when trying to send and receive messages concurrently. Here's a simplified version of my code: ```go package main import ( "fmt" "time" ) func main() { ch := make(chan string, 2) // Buffered channel with capacity 2 go func() { ch <- "Hello" ch <- "World" close(ch) }() time.Sleep(1 * time.Second) // To simulate some delay for msg := range ch { fmt.Println(msg) } } ``` I'm expecting the output to be `Hello` and `World`, but I’m getting a deadlock when I run it. I tried increasing the sleep duration and also implementing a `default` case in a select statement, but that didn’t resolve the scenario. The Go version I'm using is 1.19.2. What am I missing here? Is there a specific pattern for using buffered channels that I should follow to avoid deadlocks in this scenario? Any best practices or insights would be greatly appreciated! For context: I'm using Go on Ubuntu. How would you solve this? I'm working on a service that needs to handle this. Am I missing something obvious?