👀 Views: 36 💬 Answers: 1 📅 Created: 2025-06-07

python decorators object-oriented Python

I'm working through a tutorial and I'm following best practices but I'm trying to figure out I've been trying to implement a class decorator in Python 3.10 to modify the behavior of certain methods within a class... My goal is to log the entry and exit of methods for debugging purposes. However, I'm working with a `TypeError` when I apply the decorator to methods that expect arguments. Here's the decorator I wrote: ```python def log_method(func): def wrapper(*args, **kwargs): print(f'Entering: {func.__name__} with args: {args} kwargs: {kwargs}') result = func(*args, **kwargs) print(f'Exiting: {func.__name__}') return result return wrapper ``` Then, I applied this decorator to a method in my class: ```python class MyClass: @log_method def my_method(self, x, y): return x + y ``` When I attempt to call `my_instance.my_method(2, 3)`, I get the following behavior: ``` TypeError: wrapper() missing 2 required positional arguments: 'x' and 'y' ``` I assumed that `*args` would catch those arguments, but it seems that the decorator isn't passing them through correctly. I've also tried changing the decorator to explicitly accept the arguments, but that didn't resolve the scenario. Can anyone explain why this is happening and how I can fix it? Am I misusing decorators or is there something specific about how Python handles method calls that I’m missing? For reference, this is a production application. I'm open to any suggestions. I'm working with Python in a Docker container on Windows 10. I'd love to hear your thoughts on this. I'd really appreciate any guidance on this.