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working with TypeError when using functools.partial with dynamic function arguments in Python 3.10

👀 Views: 409 đŸ’Ŧ Answers: 1 📅 Created: 2025-06-10
python functools partial Python

Quick question that's been bugging me - I'm getting frustrated with I'm trying to use `functools.partial` to create a new function that partially applies some arguments for an existing function, but I'm running into a `TypeError`. The function I'm dealing with takes multiple arguments and I want to create a version that has some of those arguments fixed. Here's a simplified version of what I've done: ```python from functools import partial def my_function(a, b, c): return a + b + c # Creating a new function with 'a' fixed to 1 partial_function = partial(my_function, 1) # Now I want to call partial_function with the remaining arguments, but I get an behavior here result = partial_function(2) ``` When I run this, I encounter: ``` TypeError: my_function() missing 1 required positional argument: 'c' ``` I expected `partial_function` to accept two arguments, but it seems like it requires three. I also tried explicitly providing all arguments in the `partial` call like this: ```python partial_function = partial(my_function, 1, 2) ``` But that just returns a new callable that still requires the last argument `c`. I need the behavior to be that `partial_function` takes just the remaining arguments after fixing some. Is there a specific way I should structure my `partial` call, or is there something else I'm missing? Any advice on how to approach this would be greatly appreciated! I'm working on a REST API that needs to handle this. My development environment is Windows 11. Hoping someone can shed some light on this.