How to handle a PHP 8.1 warning when using array_column on a non-multidimensional array?
I'm collaborating on a project where I'm encountering a warning when trying to use `array_column` on an array that I expected to be multidimensional, but it's actually a simple array in some cases. Here's a snippet of the code that demonstrates the issue: ```php $data = [ ['id' => 1, 'name' => 'Alice'], ['id' => 2, 'name' => 'Bob'], 'Not an array', // This entry is breaking the code ]; $names = array_column($data, 'name'); ``` When I run this, I receive the following warning: ``` Warning: array_column() expects parameter 1 to be array, string given in ... ``` I’ve tried checking the structure of the `$data` variable before calling `array_column`, like this: ```php if (is_array($data)) { $names = array_column($data, 'name'); } else { // Handle the case where $data is not an array } ``` However, this doesn't resolve the issue because `$data` is indeed an array, just not consistently a multidimensional one. I also attempted to filter the array using `array_filter` to remove non-array elements before calling `array_column`, which looked like this: ```php $data = array_filter($data, 'is_array'); $names = array_column($data, 'name'); ``` While this prevents the warning, it doesn't align with how I want the data to be structured, since I might actually want to keep those non-array entries for logging. Is there a more elegant way to handle this situation without losing the original content of the array? Any suggestions on best practices for working with potentially inconsistent array structures in PHP 8.1 would be greatly appreciated. For reference, this is a production application. Hoping someone can shed some light on this.