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np.where with 2D arrays returning unexpected results when used with boolean conditions in NumPy 1.24.0

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numpy data-manipulation boolean-indexing Python

Hey everyone, I'm running into an issue that's driving me crazy. I'm relatively new to this, so bear with me. I'm working with a 2D NumPy array and trying to use `np.where()` to find indices based on a boolean condition. However, the results I'm getting seem inconsistent with what I expect. Here's a snippet of the code I wrote: ```python import numpy as np array_2d = np.array([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) condition = array_2d > 5 result = np.where(condition) print(result) ``` When I run this code, I expected to receive the indices of the elements greater than 5, but instead, I got a tuple of arrays: ``` (array([1, 2, 2]), array([2, 0, 1])) ``` This output indicates the indices of the true values, but it’s not clear how to interpret them in the context of the original 2D array. Additionally, I tried to visualize the result by reconstructing the indices: ```python for row, col in zip(*result): print(f'Value {array_2d[row, col]} at index ({row}, {col})') ``` This outputs: ``` Value 6 at index (1, 2) Value 7 at index (2, 0) Value 8 at index (2, 1) ``` While this works, I'm looking for a more straightforward way to directly extract the values that meet the condition rather than reconstructing the indices. Is there a more efficient method to achieve this, or am I missing something crucial about how `np.where()` handles 2D arrays? Thanks! For context: I'm using Python on Windows. Am I missing something obvious?