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Python - advanced patterns When Modifying a List While Iterating Over It

👀 Views: 50 đŸ’Ŧ Answers: 1 📅 Created: 2025-06-12
python list iteration modification Python

I'm having trouble with I'm working with an scenario in Python 3.9 when trying to modify a list while iterating over it. I have a list of integers, and I want to remove all even numbers during the iteration. However, the resulting list doesn't contain all the expected elements after the loop finishes. Here's a simplified version of my code: ```python numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9] for num in numbers: if num % 2 == 0: numbers.remove(num) print(numbers) ``` When I run this code, I expect to have only the odd numbers left in the list, but I get `[1, 3, 5, 7, 9]`, which is correct, but it seems like I'm missing the even numbers that should have been removed. I also tried using a copy of the list, like this: ```python for num in numbers[:]: # using a slice to create a copy if num % 2 == 0: numbers.remove(num) ``` However, I still end up with the same result. I read that modifying a list while iterating can lead to unexpected behavior, but I wasn't sure how to properly handle this situation. Is there a more reliable way to filter out the even numbers without running into issues like this? This is my first time working with Python LTS.