👀 Views: 308 💬 Answers: 1 📅 Created: 2025-06-12

Flask SocketIO asyncio Python

I'm confused about I've tried everything I can think of but Quick question that's been bugging me - I'm working with an scenario while trying to implement a real-time chat feature in my Flask application using Flask-SocketIO. The application is structured such that I'm using async functions to handle incoming messages, but I'm getting an unhandled exception when trying to emit messages to connected clients. Here's a snippet of my code: ```python from flask import Flask, render_template from flask_socketio import SocketIO, emit import asyncio app = Flask(__name__) app.config['SECRET_KEY'] = 'secret!' socketio = SocketIO(app, async_mode='eventlet') @socketio.on('send_message') async def handle_message(data): print('Received message:', data) await asyncio.sleep(1) # Simulating an async task emit('receive_message', {'msg': data['msg']}, broadcast=True) if __name__ == '__main__': socketio.run(app) ``` When I run the application and send a message, I see the following behavior in the console: ``` RuntimeError: Event loop is closed ``` I've verified that my Flask, Flask-SocketIO, and eventlet versions are compatible. I tried wrapping the `emit` call in a try/except block, but the scenario continues. I also tried using `socketio.start_background_task` instead of async functions, but I didn't achieve the desired non-blocking behavior. I would appreciate any guidance on how to properly handle async tasks with Flask-SocketIO without running into this exception. What am I doing wrong here? For context: I'm using Python on Ubuntu 20.04. This is part of a larger service I'm building. What's the best practice here?