Strange behavior with pop() on a list in Python 2.7 causing index errors
I'm reviewing some code and I'm stuck on something that should probably be simple... I'm working with an unexpected behavior when using the `pop()` method on a list in Python 2.7 that leads to `IndexError`. I've got a simple list of integers, and I'm trying to remove elements from it in a loop. Here’s a snippet of my code: ```python my_list = [1, 2, 3, 4, 5] for i in range(len(my_list)): print('Popping:', my_list.pop()) ``` I expected this to print and remove all elements from the list until it's empty, but instead, after popping the first five elements, I get an `IndexError: pop from empty list` on the sixth iteration. It seems that the loop is not aware that the list is being modified, and it continues iterating based on the initial length of `my_list`. I tried changing the loop to iterate over a copy of the list: ```python for i in my_list[:]: # Copy of the original list print('Popping:', my_list.pop()) ``` But I'm still getting the same behavior after all elements are popped. I also considered using a while loop with a condition to check if the list is empty, like this: ```python while my_list: print('Popping:', my_list.pop()) ``` This works fine, but I want to understand why the first two approaches unexpected result. Is this a known scenario with how Python 2.7 handles list mutability inside loops? Any insights on how to properly handle this situation would be greatly appreciated! This is for a REST API running on Ubuntu 20.04. For reference, this is a production CLI tool. Is there a simpler solution I'm overlooking?