👀 Views: 86 💬 Answers: 1 📅 Created: 2025-06-14

python loops indexerror

I'm having a hard time understanding I'm stuck on something that should probably be simple. I've hit a wall trying to I'm testing a new approach and I'm getting frustrated with I'm working with a puzzling scenario with a `for` loop in Python 3.9 when iterating over a range object while simultaneously modifying the list it accesses..... The code looks like this: ```python my_list = [0, 1, 2, 3, 4, 5] for i in range(len(my_list)): print(f'Current index: {i}, Value: {my_list[i]}') if my_list[i] % 2 == 0: my_list.remove(my_list[i]) ``` I'm expecting to see the current index and value of the list, but I'm running into an `IndexError` after a couple of iterations. The behavior message says `IndexError: list index out of range`. I've tried to troubleshoot by printing the list after each removal, and I noticed that it behaves unexpectedly when items are removed. I initially thought I could use `range(len(my_list))`, but that seems problematic after list modifications. Is there a better way to achieve this without causing index errors, or am I misusing the loop structure? Some guidance would be greatly appreciated! Any pointers in the right direction? This is happening in both development and production on Ubuntu 20.04. What are your experiences with this? This is part of a larger microservice I'm building. Could someone point me to the right documentation? Any examples would be super helpful. The project is a mobile app built with Python.