CodexBloom - Programming Q&A Platform

advanced patterns with Lazy Val and Recursive Function in Scala 2.13.6

πŸ‘€ Views: 0 πŸ’¬ Answers: 1 πŸ“… Created: 2025-06-14
scala lazy-val recursion performance Scala

Does anyone know how to I'm working on a personal project and I'm working on a personal project and I'm working with an scenario with a lazy val in combination with a recursive function in Scala 2.13.6..... The intention is to lazily compute a Fibonacci sequence, but it seems that the recursive calls are not behaving as expected. Here’s what I have: ```scala class Fibonacci { lazy val fib: Stream[Int] = 0 #:: 1 #:: (fib zip fib.tail).map { case (a, b) => a + b } } object Main extends App { val fibonacci = new Fibonacci println(fibonacci.fib.take(10).toList) } ``` When I run this code, it works correctly and prints the first 10 Fibonacci numbers. However, I noticed that if I attempt to access the `fib` value multiple times, I end up with a `StackOverflowError`: ```scala object Main extends App { val fibonacci = new Fibonacci println(fibonacci.fib.take(10).toList) println(fibonacci.fib.take(20).toList) // Causes StackOverflowError } ``` It seems like the recursive structure of the `lazy val` is not being handled as I anticipated. I thought that the lazy evaluation would prevent recalculating the entire stream, but it appears that each call to `fib` re-evaluates it entirely instead of caching the result. I've also tried converting `fib` to a regular val, but that leads to very high memory consumption as it computes everything eagerly. Is there a way to keep the lazy behavior while avoiding the `StackOverflowError` when accessing `fib` multiple times? I'm open to any suggestions regarding design patterns or alternative approaches that may help resolve this scenario. I'm working on a web app that needs to handle this. Am I missing something obvious? I'm on Debian using the latest version of Scala. Any suggestions would be helpful.