Sorting a List of Tuples in Python by Length of Second Element - Unexpected Results
This might be a silly question, but I can't seem to get I'm trying to sort a list of tuples in Python where each tuple contains a string and an integer... The goal is to sort primarily by the length of the string (the first element of the tuple) and secondarily by the integer (the second element of the tuple) in ascending order. However, I'm running into unexpected results with my sorting logic. Here's the code I have so far: ```python my_list = [("apple", 2), ("banana", 1), ("kiwi", 3), ("fig", 5), ("grapefruit", 4)] sorted_list = sorted(my_list, key=lambda x: (len(x[0]), x[1])) print(sorted_list) ``` I expected the output to be sorted by the length of the first element and then by the integer value as a tie-breaker. However, the output I got was: ``` [("fig", 5), ("kiwi", 3), ("apple", 2), ("banana", 1), ("grapefruit", 4)] ``` This output doesn't seem to reflect the sorting I intended. I've checked that the `key` function is supposed to return a tuple for sorting, and I thought I followed the correct logic. I'm using Python 3.10 and I've also tried using the `list.sort()` method with the same key function, but I get the same result. What am I missing here? Are there specific edge cases I should be aware of when sorting lists of tuples? Any insights would be appreciated! My development environment is Windows. How would you solve this? This is part of a larger desktop app I'm building. Is there a simpler solution I'm overlooking? My development environment is CentOS. Thanks for any help you can provide! What's the best practice here?