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advanced patterns when using 'interp1' with extrapolation in MATLAB R2023b

👀 Views: 0 đŸ’Ŧ Answers: 1 📅 Created: 2025-06-16
matlab interp1 extrapolation MATLAB

Could someone explain I'm reviewing some code and I'm optimizing some code but I'm trying to debug Hey everyone, I'm running into an issue that's driving me crazy... I've searched everywhere and can't find a clear answer. I'm working with unexpected behavior when using the `interp1` function for interpolation with extrapolation in MATLAB R2023b. Specifically, when I set the `method` to 'linear' and provide extrapolation points outside the data range, the results seem incorrect. For example, I have the following data: ```matlab x = [1, 2, 3, 4, 5]; y = [10, 20, 30, 40, 50]; ``` I want to interpolate for values of `x` that extend beyond my provided range: ```matlab xq = [0, 1.5, 2.5, 3.5, 5.5, 6]; ``` When I run: ```matlab yq = interp1(x, y, xq, 'linear', 'extrap'); disp(yq); ``` The output I receive is: ``` 0 15 25 35 55 NaN ``` The extrapolated value for `x = 6` is returning `NaN`, which is unexpected. I have tried changing the extrapolation method to 'pchip', but I still encounter the same scenario. I also verified my input arrays and ensured they are not empty and are the right dimensions. What could be causing this scenario, and how can I correctly obtain extrapolated values using `interp1`? Am I missing a crucial configuration or step here? How would you solve this? I'm working on a API that needs to handle this. Is there a better approach? I'm using Matlab 3.9 in this project. What would be the recommended way to handle this? Has anyone else encountered this? The stack includes Matlab and several other technologies. What would be the recommended way to handle this?