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Bash script not passing variable correctly to xargs with subprocesses

👀 Views: 358 đŸ’Ŧ Answers: 1 📅 Created: 2025-06-17
bash xargs subprocesses

I'm trying to configure I've looked through the documentation and I'm still confused about I tried several approaches but none seem to work. I'm working with an scenario where my bash script is not passing a variable correctly to the `xargs` command when using it with subprocesses. I'm using bash version 5.1.4 on Ubuntu 21.10. The goal is to read a list of filenames from a text file and pass each filename to a command for processing. However, the variable seems to be empty when the command executes. Here's the relevant part of my script: ```bash #!/bin/bash input_file="file_list.txt" # Read the input file and process each line with xargs cat "$input_file" | xargs -I {} sh -c 'echo Processing: {}; some_command --file="{}"' ``` The `file_list.txt` contains the following: ``` file1.txt file2.txt file3.txt ``` When I run the script, I expect to see output like: ``` Processing: file1.txt Processing: file2.txt Processing: file3.txt ``` However, instead, I see: ``` Processing: Processing: Processing: ``` I tried debugging by echoing the variable directly in the `sh -c` command and it consistently returns empty. I also ensured that the filenames are correctly read by running `cat "$input_file"` separately, which shows the expected filenames. I've tried using both single and double quotes around `{}` but it doesn't seem to affect the outcome. What am I missing? Is there a better approach to achieve this that ensures the correct variable is passed to the command? I'm working on a web app that needs to handle this. Any help would be greatly appreciated! My development environment is Windows. Thanks in advance! This is part of a larger application I'm building. I'd really appreciate any guidance on this. I'm developing on Windows 10 with Bash. Thanks in advance!