How to properly use the `map` function on Option with nested Options in Scala?
I've searched everywhere and can't find a clear answer. I've been banging my head against this for hours. After trying multiple solutions online, I still can't figure this out... I'm working with Scala 2.13 and trying to process some nested `Option` values. I have a situation where I receive an `Option[Option[String]]` and I want to transform it into an `Option[String]` using the `map` function, but I'm confused about how to handle the inner `Option`. Here's what I have so far: ```scala val nestedOpt: Option[Option[String]] = Some(Some("Hello")) val result: Option[String] = nestedOpt.map(_.map(_.toUpperCase)) ``` The intention here is to get a single `Option[String]` containing "HELLO" if the value is present. However, I've noticed that my current implementation results in `Option[Option[String]]` instead of `Option[String]`. I understand that the inner `map` is working correctly, but it seems I'm not flattening the result into a single `Option`. I've also tried using `flatMap`, but I'm not sure how to apply it effectively in this context: ```scala val resultWithFlatMap: Option[String] = nestedOpt.flatMap(_.map(_.toUpperCase)) ``` This still feels a bit unclear, especially when considering the case where `nestedOpt` is `None`. How can I properly handle this situation to achieve a single `Option[String]`? Is there a more concise or idiomatic way to achieve this in Scala? Thanks for your help! I'm working on a web app that needs to handle this. Thanks, I really appreciate it! I'm working on a microservice that needs to handle this. Any suggestions would be helpful.