implementing using 'trap' in a nested Bash script leading to unexpected exit codes
Could someone explain I'm having trouble with a nested Bash script where I'm using the `trap` command to handle cleanup on exit. My main script calls a secondary script in a subshell, and I want to ensure that certain cleanup tasks run when either script exits or is terminated. However, I'm seeing unexpected exit codes that don't match what I expect based on the commands executed. For instance, if the second script exits with a non-zero status, I want to capture that and perform some cleanup in the main script. Here's a simplified version of what I have: ```bash # main_script.sh #!/bin/bash trap 'echo "Cleaning up..."; exit 1' EXIT ./nested_script.sh echo "Main script finished with exit code: $?" ``` And the nested script looks like this: ```bash # nested_script.sh #!/bin/bash trap 'echo "Nested cleanup..."; exit 1' EXIT # Simulating an behavior false ``` When I run `main_script.sh`, it exits with code 0, which is not what I expected since `nested_script.sh` should have exited with code 1. I've tried adding `set -e` to both scripts, but it doesn't seem to affect the exit code propagation as I thought it would. How can I ensure that the exit code from the nested script is properly propagated back to the main script, and the traps execute as needed? Iām running Bash 5.1 on Ubuntu 20.04. My development environment is Windows 11. Any help would be greatly appreciated!