C# - implementing Task.WhenAll and handling Handling in Asynchronous Operations
I'm maintaining legacy code that Does anyone know how to I'm working with a question when using `Task.WhenAll` to run multiple asynchronous operations in parallel. I expect that if one of the tasks fails, I should be able to catch the exception for that specific task and proceed accordingly. However, I'm finding that the entire operation fails and I'm not able to handle each exception individually. I'm using .NET 6 and here's my setup: ```csharp public async Task ProcessTasksAsync() { var tasks = new List<Task>(); for (int i = 0; i < 5; i++) { int taskId = i; tasks.Add(Task.Run(async () => { if (taskId == 2) // Simulate an behavior for task 2 { throw new InvalidOperationException("behavior in task " + taskId); } await Task.Delay(1000); // Simulate some async work Console.WriteLine("Task " + taskId + " completed."); })); } try { await Task.WhenAll(tasks); } catch (Exception ex) { Console.WriteLine("Caught an exception: " + ex.Message); } } ``` When I run this code, I see that the exception thrown in task 2 is caught, but I don't get to see the output for the other tasks that completed successfully. Instead, I see: ``` Caught an exception: behavior in task 2 ``` What I would like to achieve is to handle exceptions for each task individually, so that I can log the errors but still see which tasks completed successfully. I've considered using `ContinueWith`, but I'm not sure how to implement it effectively in this case. Any suggestions on how to modify my approach to achieve this? Thanks! I appreciate any insights! I'd really appreciate any guidance on this.