👀 Views: 14 💬 Answers: 1 📅 Created: 2025-06-21

bash getopts scripting

I just started working with I'm integrating two systems and I'm prototyping a solution and I'm testing a new approach and I tried several approaches but none seem to work... Quick question that's been bugging me - I'm working on a Bash script where I need to handle multiple options passed as arguments... However, I'm working with issues when the options are passed together, and I need to seem to parse them correctly in a case statement. For instance, when I run the script like this: ```bash ./myscript.sh -a -b -c ``` I expect it to process options `-a`, `-b`, and `-c`, but my current implementation only recognizes the first option `-a`. Here’s how I’ve structured my case statement: ```bash while getopts "abc" opt; do case $opt in a) echo "Option A selected" ;; b) echo "Option B selected" ;; c) echo "Option C selected" ;; *) echo "Invalid option" ;; esac done ``` I've tried using `getopt` instead of `getopts`, but the syntax seems more complicated for what I need. When I run the script, it only processes `-a`, and I never see the messages for `-b` or `-c`. I also tried passing the options with spaces like this: ```bash ./myscript.sh -a -b -c ``` but the outcome remains the same. Am I missing something in the execution flow, or is there a question with how I'm using `getopts`? Any help would be appreciated! For context: I'm using Bash on Windows. Am I missing something obvious? Any help would be greatly appreciated! I'm working with Bash in a Docker container on Windows 11. I'd love to hear your thoughts on this. Any suggestions would be helpful. I've been using Bash for about a year now. I'd be grateful for any help. I'm developing on CentOS with Bash.