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Unexpected infinite loop when using a for loop with a generator in Python 3.10

👀 Views: 186 đŸ’Ŧ Answers: 1 📅 Created: 2025-06-26
python generator itertools Python

I'm sure I'm missing something obvious here, but I'm sure I'm missing something obvious here, but I'm currently working on a data processing task in Python 3.10, where I need to read integers from a generator and process them in chunks... However, I'm working with an unexpected infinite loop when I attempt to iterate over the generator within a for loop. Here's a simplified version of the code: ```python from itertools import islice def number_generator(): for i in range(10): yield i num_gen = number_generator() for chunk in iter(lambda: list(islice(num_gen, 3)), []): print("Processing chunk:", chunk) ``` I expected the output to show each chunk of three numbers from the generator, but instead the loop runs indefinitely, and I need to figure out why. I've checked the generator function and it seems to yield values correctly. Additionally, I've tried adjusting the chunk size and even placed print statements inside the generator, but the question continues. When I run the code, I see no errors, but I just keep getting the same output over and over, which suggests the generator is not producing new values after the first iteration. I suspect it has something to do with how I'm using `islice` in conjunction with the lambda function. Is there a better way to structure this loop to avoid an infinite iteration? Any insights or suggestions would be greatly appreciated! For context: I'm using Python on Linux. Any ideas what could be causing this? This is part of a larger API I'm building. How would you solve this? My team is using Python for this mobile app. Is there a better approach?