MySQL 8.0 - implementing CASE Statement and Sorting in Subqueries
I need help solving Quick question that's been bugging me - After trying multiple solutions online, I still can't figure this out. I'm working on a project and hit a roadblock. I'm experiencing unexpected behavior when using a `CASE` statement within a subquery and trying to sort the results. I have a table called `orders` that contains `id`, `status`, and `created_at` columns. The `status` can be 'pending', 'completed', or 'cancelled'. I'm trying to select the `id` and a custom `status_order` based on the value of `status`, and then sort the results by `status_order` in ascending order. However, the sort order doesn't seem to reflect the logic in my `CASE` statement. Here’s my query: ```sql SELECT id, CASE status WHEN 'pending' THEN 1 WHEN 'completed' THEN 2 WHEN 'cancelled' THEN 3 ELSE 4 END AS status_order FROM orders ORDER BY status_order; ``` When executing this query, I expect the results to be ordered as 'pending', 'completed', 'cancelled', but instead, the order seems arbitrary. I’ve tried running the query directly in MySQL Workbench and also through a Node.js application using the `mysql2` library, yet I get the same results. I also tried simplifying my query to exclude the `CASE` statement and just sort by the `status` column directly, which worked fine, so it seems specific to how I'm using the `CASE`. The data set is relatively small, containing about 500 rows. I'm running MySQL version 8.0.26. Is there something I'm overlooking in the syntax or logic that could lead to this unexpected sorting behavior? Any insight would be greatly appreciated! For context: I'm using Sql on Linux. Is there a better approach? This is part of a larger web app I'm building. Any ideas what could be causing this? Thanks for taking the time to read this!